An object is placed 15cm from a thin lens of focal length +5cm. (a) (3pt15cms) Locate the image of the object (both graphically and numerically). (b) (2pts) Describe the image of the object (real or virtual, inverted or upright, enlarged or shrunk). A second thin lens of focal length +10cm is now placed 20cm away from the first lens on the outgoing ...
There are 2.54 centimeters in one inch. So take your measurement in inches and multiply it by 2.54 to change the unit to centimeters. In this case, the answer is 38.1 centimeters.Algebraic Steps ...
Now consider a diverging lens with focal length f=−15cm, producing an upright image that is 5/9 as tall as the object. Part E. Is the image real or virtual? Think about the magnification and how it relates to the sign of s′. Is the image real or virtual? Think about the magnification and how it relates to the sign of .
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